Question

if cot Theta=13/8 then evaluate (2+2 sin theeta) (1-sin theta)/(1 +cos theta) (2-2cos theta​

Answer 1

Answer:

cotx =13/8 (given)

(2+2sinx)(1-sinx)/(1+cosx)(2-2cosx)

taking 2 common from Nr and Dr we get

(1+sinx)(1-sinx)/(1+cosx)(1-cosx)

(1-sin2x)/(1-cos2x)          this is sin square x

= cos (square) x/sin(square)x

cot(square)x = (13/8)(13/8)= 169/64

Ans is 169/64