If cot theta = 13/8
then evaluate (2 + 2sin theta) (1 - sin theta) ÷ (1 + cos theta) (2 - 2cos theta)
pls help!!
Answers
Answered by
1
Step-by-step explanation:
given cotθ=13/8
(2+2sinθ)(1-sinθ)/(1+cosθ)(2-2cosθ)
=2(1-sin²θ)/2(1-cos²θ)
=cos²θ/sin²θ
=cot²θ
=(13/8)²
=169/64
Similar questions