Question

if cot theta =15/8,evalute=(2+2sin theta)(1-sin theta)/(1+cos theta )(2-2cos theta)

Answer 1

p(x)  =  (2+ 2sinA) (1- sinA)/ (1 + cosA) (2 - 2cosA) = 
2(1 + sinA)(1-sinA) / (1 + cosA) (1 - cosA) (2)
[ 1 - (sinA)^2 ] / [1 - (cosA) ^ 2]
(cosA)^2 / (sinA) ^ 2                             ( as sinA^2 + cosA^2 = 1)
cotA^ 2                    (as cosA / sinA = cotA)
but given  that cotA = 15 / 8
cotA ^ 2 = 225 / 64
therefore p(x) = 225 / 64