Math, asked by anshagarwalshirdisai, 1 year ago

If cot theta = 2, find the value of 2 sin theta - 3 cos they divided by 2 sin theta+ 3 cos theta

Answers

Answered by fanbruhh
9
HEY

HERE IS ANSWER.

 \bf{answer =  \frac{ - 1}{2} }

 \bf{step \: by \: step \: explanation}

Given: -

 cot \theta=2


To find:-
 \frac{2 \sin \theta - 3cos \theta }{2sin \theta  + 3cos \theta}
pp

cot \theta =  \frac{2}{1}
since

cot theta=b/p

means base upon perpendicular.

hence

base=2 units

perpendicular=1 units

so now

hypotenuse=

(h)^2=b^2+P^2

so

h^2=2^2+1^2

h^2=4+1

h^2=5

h =  \sqrt{5}


so

 \sin \theta =  \frac{perpendicular}{hypotenuse}

 \sin \theta =  \frac{1}{ \sqrt{5} }
  \cos \theta =  \frac{base}{hypotenuse}

 \cos \theta =  \frac{2}{ \sqrt{5} }

so now

put value get result


please see in attachment.

HOPE IT HELPS

THANKS
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