if cot theta= 2√ mn /m+n find the value of sin tetha
(given m>n)
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cos Theta = b/h
the p^2 + b^2 = h^2
p^2 + (2√mn)^2 = (m+n)^2
p^2 + 4mn = m^2 + n^2 + 2mn
p^2 = m^2 + n^2 -2mn
p^2 = (m-n) ^2
p = m-n
sin theta = p/h
= (m-n) / (m+n)
the p^2 + b^2 = h^2
p^2 + (2√mn)^2 = (m+n)^2
p^2 + 4mn = m^2 + n^2 + 2mn
p^2 = m^2 + n^2 -2mn
p^2 = (m-n) ^2
p = m-n
sin theta = p/h
= (m-n) / (m+n)
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