If cot theta =2,where theta is in third quadrant. Find the value of tan theta and cos theta
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1+ cot²theta= cosec²theta
1+4= cosec²theta
cosec²theta= 5
cosect theta = √5
therefore sin theta= 1/√5
cot theta= cos theta/sin theta
2= cos theta /(1/√5)
cos theta= 2/√5.....(1st answer )
tan theta= 1/cot theta= 1/2.....(2nd answer)
1+4= cosec²theta
cosec²theta= 5
cosect theta = √5
therefore sin theta= 1/√5
cot theta= cos theta/sin theta
2= cos theta /(1/√5)
cos theta= 2/√5.....(1st answer )
tan theta= 1/cot theta= 1/2.....(2nd answer)
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