Question

If cot theta=2mn/m^2-n^2, then sec theta=​

Answer 1

Answer:

$\sec(theta) = \frac{ {m}^{2} + {n}^{2} }{2mn}$

Step-by-step explanation:

Cot theta = B/P

B = 2mn

P = m^2 - n^2

H^2 = p^2 + b^2

H^2 = 4m^2n^2 + m^4 + n^4 - 2m^2n^2

H^2 = m^4 + n^4 + 2m^2n^2

H^2 = ( m^2 + n^2) ^2

H = m^2 + n^2

Now, sec theta = H/ B

Sec theta = m^2 + n^2 / 2mn