if cot theta = √3, then find the value of sin 3theta
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Answer:
Given,
cotθ=31⇒cotθ=cot60o⇒θ=60o∴(2−sin2θ1−cos2θ)
Putting the value of θ we get,
=2−sin260o1−cos260o=2−(23)21−(21)2=2−431−41=48−344−1=45
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