Question

if cot theta = √3, then find the value of sin 3theta​

Answer 1

Answer:

Given,

cotθ=31⇒cotθ=cot60o⇒θ=60o∴(2−sin2θ1−cos2θ)

Putting the value of θ we get,

=2−sin260o1−cos260o=2−(23)21−(21)2=2−431−41=48−344−1=45