Question

If cot theta = 4/3, evaluate (4 sin theta + 3 cos theta) / (4 sin theta - 3 cos theta)

Answer 1

cotθ = 4/3 x = 4, y = 3 solve for r . . x^2 + y^2 = r^2 4^2 + 3^2 = r^2 16+9=r^2 r^2 = 25 r = 5 sin θ = y/r --> 3/5 cosθ = x/r --> 4/5