Question

If cot theta = 4/3,then cos square theta - sin square theta is equal to

Answer 1

Answer:- 1/5

SOLUTION:-

cot(theta) = 4/3 = base(b) / perpendicular (p)

So, base(b) = 4 & perpendicular (p) = 3

Hence ,

$hypotenus(h) = \sqrt{ {4}^{2} + {3}^{2} }$

$= \sqrt{16 + 9}$

$= \sqrt{25}$

h = 5

Now,

cos^2(theta) - sin^2(theta)

= b/h - p/h

= 4/5 - 3/5

= 1/5

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Enjoy Maths!!

(SK Study Point Siliguri)

Answer 2

Answer:

Answer:- 1/5

SOLUTION:-

cot(theta) = 4/3 = base(b) / perpendicular (p)

So, base(b) = 4 & perpendicular (p) = 3

Hence ,

hypotenus(h) = \sqrt{ {4}^{2} + {3}^{2} }hypotenus(h)=

4

2

+3

2

= \sqrt{16 + 9}=

16+9

= \sqrt{25}=

25

h = 5

Now,

cos^2(theta) - sin^2(theta)

= b/h - p/h

= 4/5 - 3/5

= 1/5