Question

If cot theta =40/9,find the value of cosec theta and sin theta?

Answer 1

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$\cot( \alpha ) = \frac{40}{9} \\ \\ \\ { \csc}^{2} ( \alpha ) = 1 + { \cot( \alpha ) }^{2} \\ \\ { \csc( \alpha ) }^{2} = 1 + \frac{ {40}^{2} }{ {9}^{2} } \\ \\ { \csc( \alpha ) }^{2} = 1 + \frac{1600}{81} \\ { \csc( \alpha ) }^{2} = \frac{1681}{81} \\ \\ \csc( \alpha ) = \frac{41}{9} \\ \\ \\ \sin( \alpha ) = \frac{9}{41} \\ \\ \\ \\ hope \: it \: helpful$

Answer 2

Answer:

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\cot( \alpha ) = \frac{40}{9} \\ \\ \\ { \csc}^{2} ( \alpha ) = 1 + { \cot( \alpha ) }^{2} \\ \\ { \csc( \alpha ) }^{2} = 1 + \frac{ {40}^{2} }{ {9}^{2} } \\ \\ { \csc( \alpha ) }^{2} = 1 + \frac{1600}{81} \\ { \csc( \alpha ) }^{2} = \frac{1681}{81} \\ \\ \csc( \alpha ) = \frac{41}{9} \\ \\ \\ \sin( \alpha ) = \frac{9}{41} \\ \\ \\ \\ hope \: it \: helpful

Step-by-step explanation: