If cot theta 40/9 find the values of cosec theta and sin theta
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cosec theta= 41/9 and sin theta = 9/41, i think u wanted cos theta but due to typing error u wrote cosec so cos theta = 40/41
Step-by-step explanation:
cot theta is base / perpendicular, so it a let a right angled triangle ABC and theta is angle A and base of triangle is AC and perpendicular is BC,
as we know the value of cot theta so we know the length of AC= 40 abd length of BC= 9
NOW , according to Pythagoras
side AB=41 , NOW we know all side lengths
so sin theta is perpendicular/hypotenuse = 9/41
cosec theta is =1/sin theta = 41/9
and cos theta= base/hypotenuse = 40/41
PLEASE DO LIKE AS IT TOOK SO LONG TO TYPE
THANKYOU ALL THE BEST
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