Question

If cot theta = 40 upon 9, then find the value of cosec theta?

Answer 1

$\csc( \alpha ) = \sqrt{ { \cot( \alpha ) }^{2} + 1 } \\ = \sqrt{ ({40 \div 9})^{2} + 1 } = \sqrt{1600 \div 81 + 1} = \sqrt{1600 + 81 \div 81} = \sqrt{1681 \div 81} \\ 41 \div 9$
is the required answer