If cot theta = 7/8 evaluate (1+sin theta )(1-sin theta )/( 1- cos theta)(1+cos theta)
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Answered by
1
Answer:
49/64.
Step-by-step explanation:
Given Cot θ = 7/8
Now ,
(1 + sin θ)(1 - sinθ)/( 1 - cos θ)(1 + cos θ)
= 1 - Sin²θ / 1 - Cos²θ (∵ (a + b) (a-b) = a² - b²)
= Cos² θ/Sin²θ ( ∵ Sin²θ + Cos²θ = 1)
= Cot²θ
= (7/8)²
= 49/64.
Answered by
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Answer:
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