Question

if cot theta=7/8, evaluate(: a)( 1+sin theta) (1_sin theta)/(1+cos theta) (1_cos theta)

Answer 1

Cot theta=7/8=base/hypotinious
Let base be 7x and h(hypotinious) be 8x.
By Pythagoras Theorem :-
H^2= b^2 + p^2
(8x)^2=(7x)^2 + b^2
64x^2-49x^2=b^2
b^2=15x^2
b=under root 15x^2
b=under root15 × x
now you can put it in formulas and get the answer.