Question

if cot theta=7/8 find (1+sin theta)×(1-sin theta)/(1+cos theta)×(1-cos theta)


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Answer 1

Step-by-step explanation:

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Answer 2

cot teta= 7/8

By Pythagoras theorem :

H^2= P^2 - B^2

= 8^2- 7^2

= 64 - 49

= √113

therefore,

sin teta= P/H= 8/√113

cos teta= B/H= 7/√113

= 1- sin^2teta/1-cos^teta

= 1-(8/√113)^2/1-(7/√113)

= 49/64

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