Math, asked by anuskabasnet17, 3 months ago

if cot theta = 7/8 find the value of (1+sin theta ) ( 1-sin theta )/(1+cos theta ) (1-cos theta)​

Answers

Answered by gsingh5be19
1

Answer:

cot theta =7/8

now

(1+sin theta) (1-sin theta)/(1+cos theta) (1-cos theta)

=(1-sin^2 theta)/(1-cos^2 theta)

=cos^2 theta/sin^2 theta

=cot^2 theta

=(7/8)^2

=49/64

Step-by-step explanation:

using (a+b)(a-b)= a^2 -b ^2

Answered by arpanaial06
1

Answer:

 \frac{49}{15}

plz mark me as a brainlest

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