if cot theta = 9/40, find the values of cosec theta and sec theta
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We have, Cot theta = 9/40
Therefore, cosec theta = √ 1 + cot² theta
= √ 1 + ( 9/40 )²
= √ 1 + 81/1600
= √ 1681/1600
= 41/40
Now, cot theta = 9/40
tan theta = 1/cot theta = 40/9
Therefore, sec theta = √ 1 + tan²theta
= sec theta = √1+ ( 40/9)²
= √ 1681/81
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