Question

If cot theta+cos theta = m and cot theta - cos theta = n then (m² - n²)² is equal to:​

Answer 1

Answer:

please mark as brainliest answer.

Step-by-step explanation:

cottheta + costheta = m

cottheta - costheta = n

now,

(m² - n²)² = [(m - n)(m + n)]²

[ (cottheta + costhet - cottheta + costheta)(cottheta - costhet + cottheta + costheta) ]²

[ (2costheta)(2cottheta) ] ²

[ 16(cot²theat) . (cos²theta) ]-----------( 1 )

now,

16mn

16(cottheta + costheta)(cottheta - costheta)

16(cot²theta - cos²theta)

16(cos²theta / sin²theta - cos²theta)

16(cos²theta - cos²theta . sin²theta)/sin²theta

16(cos²theta(1 - sin²theta)/sin²theta

16(cos²theta . cos²theta)/sin²theta

16(cos²theta/sin²theta . cos²theta)

16(cot²theta . cos²theta)------------( 2 )

from-----( 1 ) & -----( 2 )

[(m² - n²)]² = 16(mn)

I HOPE ITS HELP YOU

Answer 2

Answer:

16mn

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Hope it helps!(◕ᴗ◕✿)