if cot theta+cos theta = p and cot theta-cos theta=q then the value of p^2-q^2 is
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Heya mate
here is your answer
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here is your answer
I hope this will help you....✌️✌️
thank u:-)
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Swarup1998:
Nicely answered! :clap:
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p^2-q^2
=(cot theta +cos theta)^2 -(cot theta - cos theta)^2
=cot^2 theta + 2cot theta cos theta +cos^2 theta -(cot^2 theta -2cot theta cos theta +cos^2 theta)
=cot^2 theta +2cot theta cos theta + cos^2 theta -cot^2 theta + 2cot theta cos theta - cos^2 theta
=2 cot theta cos theta + 2cot theta cos they
=4 cot theta cos theta
or
=4 cos^2 theta /sin theta
=(cot theta +cos theta)^2 -(cot theta - cos theta)^2
=cot^2 theta + 2cot theta cos theta +cos^2 theta -(cot^2 theta -2cot theta cos theta +cos^2 theta)
=cot^2 theta +2cot theta cos theta + cos^2 theta -cot^2 theta + 2cot theta cos theta - cos^2 theta
=2 cot theta cos theta + 2cot theta cos they
=4 cot theta cos theta
or
=4 cos^2 theta /sin theta
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