Question

If cot theta equal to 3/4 prove that root sec teta - cosec theta by sec theta + cosec theta is equal to 1 by root 7​

Answer 1

Step-by-step explanation:

let the triangle be ABC,

by pythagoras theorem

AC^2 = AB^2+BC^2

x^2=16+9

x= root25

x=5

sec theta =5/3

cosec theta = 5/4

root sec teta - cosec theta by sec theta + cosec theta

=root (5/3-5/4)/(5/3+5/4)

= root (20-15/4)/(20+15/4)

=root(5/4)/(35/4)

=root 1/7

=1/root7