Question

If cot theta equals to 7 by 8,
evaluate : (i) (1+sin theta )( 1 - sin theta)by (1+cos theta)(1-cos theta)
(ii) cot sq theta

Answer 1

(1+sinΦ)(1-sinΦ)/(1-cosΦ)(1+cosΦ)

1 - sin^2Φ/1-cos^Φ

cos^2Φ/sin^Φ

cot^Φ

(7/8)^2 = 49/64

Hope it helped you