if cot theta =tan theta. so find the value of cos2theta
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Step-by-step explanation:
The equation 6x
4
−13x
3
−35x
2
−x+3=0 has all rational coefficients.
As 2+
3
is a root, its conjugate 2−
3
is also a root of the equation in order to have rational coefficients.
Hence, (x−(2+
3
))(x−(2−
3
)) is a factor of the equation.
⇒(x
2
−4x+1) is a factor of 6x
4
−13x
3
−35x
2
−x+3=0
⇒6x
4
−13x
3
−35x
2
−x+3=(x
2
−4x+1)(ax
2
+bx+c)
On comparing the coefficients, we get
a=6,b=11,c=3
Hence, 6x
4
−13x
3
−35x
2
−x+3=(x
2
−4x+1)(6x
2
+11x+3)
⇒6x
4
−13x
3
−35x
2
−x+3=(x
2
−4x+1)(2x+3)(3x+1)
Hence the roots are
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