Question

If cot x =-3/4,x in 2nd quadrant,then find sin x/2,cos x/2,tanx/2.​

Answer 1

Answer:

$cotx = \frac{ - 3}{4}$

In 2nd quadrant,

To find :

Sin x/2, cos x/2,tan x/2

Let us take right angle triangle,

$ac {}^{2} = ab {}^{2} + bc {}^{2}$

$ac {}^{2} = 4 {}^{2} + ( - 3 {}^{2} )$

$ac {}^{2} = 16 + 9 = 25$

$ac = \sqrt{25 } = 5$

Then,

$\sin \frac{x}{2} = \frac{4}{5 \div 2}$

$sin \frac{x}{2} = \frac{2}{5}$

$\cos \frac{x}{2} = \frac{ - 3}{5 \div 2} = - \frac{1}{5}$

$\tan \frac{x}{2} = \frac{4}{3 \div 2} = - \frac{2 }{3}$

❄️Hope this helps u

Cos and tan will be negative sign because, in the second quadrant only sine and cosce are positive.

❄️Short method to get sign convention,

ALL STUDENTS TAKE COFFE

❄️1ST QUADRANT = ALL TRIGONOMETRY FUNCTIONS IS +

❄️2ND QUADRANT = SINE AND COSECANT IS +

❄️3RD QUADRANT = TAN AND COT IS +

❄️4TH QUADRANT = COS AND SEC IS +

Tag me as brainliest ❤️