if cot x is 5/12 then what is the value of cos x + sec x
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194/65
Step-by-step explanation:
cosx/sinx=5/12
cos^2 x+sin^2 x =1
dividing by cos^2 x
1+(sin^2 x / cos^2 x ) = 1/cos^2 x
1+(12/5)^2 = 1/cos^2 x
1+ (144/25) = 1/cos^2 x
169/25 = 1/cos^2 x
cosx=5/13
cosx+ secx = 5/13 + 13/5
=194/65
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