Question

If cot2A = tan(A-39), where 2A is an acute angle, the value of A is​

Answer 1

Tan(90-2A)=tan(A-39)
Equate the angle then,
90-2A=A-39
90+39=A+2A
129=3A
129/3=A
43=A

Answer 2

Answer:

Step-by-step explanation:

cot2A = tan (A - 39°)

cot (90°- 2A ) = cot (A - 39°) [∵cotA=tan(90−θ)]

90° - 2A = A - 39°

90° + 39° = A + 2A

3A = 129°

A = 129/3

A = 43°