Question

if cot9bita=sin bita and 9bita<90° find value of tan5bita​

Answer 1

Answer:

Cos9A =sinA

cos9A=sin(90-A)

cos9A=cos(90-A)

9A=90-A

10A=90

A=9

tan5A=tan5(9)=tan45=1

Answer 2

HERE IS YOUR ANSWER MATE......;

$= > 1$

HOPE ITS HELPFUL.....:-)