Math, asked by Praful5251, 9 months ago

If cotA=1√3, show that sin'2 A√1- cos'2 A=3√5

Answers

Answered by Anonymous
9

Answer:

LHS=(1+tan2A)2tanA​+(1+cot2A)2cotA​

(sec2A)2tanA​+(cosec2A)2cotA​

=cos4A1​cosAsinA​​+sin4A1​sinAcosA​​

=sinAcos3A+cosAsin3A

=sinAcosA[sin2A+cos2A]

=sinAcosA=RHS

Hence proved.

Step-by-step explanation:

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