Question

if cotA=12/5 then (sinA + cosA) ×cosecA = ?​

Answer 1

Answer:

(sinA + cosA) ×cosecA = 17/5

Step-by-step explanation:

cotA = b/h = 12/5

then let,

b= 12x

h= 5x

we know that,

(p)^2= (b)^2 + (h)^2

= 144 x^2 + 25 x^2

= 169 x^2

=> p= 13 x

then,

sinA = h/p = 5/13

cosA= b/p = 12/13

cosecA = p/h = 13/5

then,

(sinA+cosA)cosecA

= (5/13 + 12/13)×13/5

= 17/5