if cotA =2/5 the find 4+4tan²A
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Cot A = 2/5
Tan A = 5/2
4 +4 Tan^2 A =4 + 4 (5/2)^2
= 4 + 4 (25/4)
4 + 25 = 29
Tan A = 5/2
4 +4 Tan^2 A =4 + 4 (5/2)^2
= 4 + 4 (25/4)
4 + 25 = 29
prototype123:
what if instead of cotA there is cosA
Cos A = 4/5 =》base/hypo = 4/5
find perpendicular from pythahorous theorem nd then put the value of tan A
Answered by
1
Cot A = 2/5
Tan A = 1/cot A
So, Tan A = 1/2/5
= 5/2
Tan^2 A = 25/4
Hence
4 + 4tan^2 A
= 4 + 4 x 25/4
= 4 + 25
= 29
Peace! Good Luck Man!
Tan A = 1/cot A
So, Tan A = 1/2/5
= 5/2
Tan^2 A = 25/4
Hence
4 + 4tan^2 A
= 4 + 4 x 25/4
= 4 + 25
= 29
Peace! Good Luck Man!
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