Question

If cotA = 3/4 find 3cosA+ 5 sinA , A is in 1st quadrant

Answer 1

Answer:

Step-by-step explanation:

Given cotA=3/4

So, b=3k and p=4k

So, h=√(3k)²+(4k)²

= √(9k²+16k²)

=√25k²

= 5k.

cosA = b/h=3k/5k=3/5

sinA=p/h= 4k/5k =4/5

3cosA+5sinA=3(3/5)+5(4/5)

=(9/5)+4

=29/5