if cotA =3\5then find the value of sinA+cosA\sinA-cosA
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Answer:
4
Step-by-step explanation:
cot A = 3/5
(sinA + cosA)/(sinA - cosA)
divide numerator and denominator by sinA, we get:
= (sinA/sinA + cosA/sinA)/(sinA/sinA - cosA/sinA)
= (1 + cotA) / (1 - cotA)
Put the value of cotA = 3/5, we get:
= (1 + 3/5) / (1 - 3/5)
= (8/5) / (2/5)
= 4
[Hope you got that, if still having any doubt, feel free to ask in the Comment]
Thank you!
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