Math, asked by sunilchaparwal, 11 months ago

if cotA =3\5then find the value of sinA+cosA\sinA-cosA​

Answers

Answered by Raja395
1

Answer:

4

Step-by-step explanation:

cot A = 3/5

(sinA + cosA)/(sinA - cosA)

divide numerator and denominator by sinA, we get:

= (sinA/sinA + cosA/sinA)/(sinA/sinA - cosA/sinA)

= (1 + cotA) / (1 - cotA)

Put the value of cotA = 3/5, we get:

= (1 + 3/5) / (1 - 3/5)

= (8/5) / (2/5)

= 4

[Hope you got that, if still having any doubt, feel free to ask in the Comment]

Thank you!

Similar questions