Question

If cotA=4/3 find the value of 1-tan square A by 1 + tan square A

Answer 1

Step-by-step explanation:

cot A= 4/3

we know that

tan A= 1/cotA

hence

tan A= 3/4

now

we have to find

1-tan square A/ 1+tan square A

1-9/16/1+9/16

7/25

Answer 2

$cota = \frac{4}{3} \\ tana = \frac{1}{cota} = \frac{3}{4} \\ \\ \frac{1 - {tan}^{2} a}{1 + {tan}^{2} a} = \frac{1 - ( { \frac{3}{4} })^{2} }{1 + ( { \frac{3}{4} })^{2} } \\ \\ = \frac{ \frac{16 - 9}{16} }{ \frac{16 + 9}{16} } \\ \\ = \frac{7}{25}$