Question

If cotA = a/b. find the value of asinA - bcos A/asin A + bcos A​

Answer 1

Step-by-step explanation:

Cot A = b/a

→ cos A / sin A = b/a ,

→cos A = b/a sin A .

then asin A - b cos A

= a sin A - b x a/b siA

= asin A - a sin A

= 0 ,

and ,

asin A + b cosA

= a sin A + b x a/b sin A

= a sin A + a sin A

= 2 sin A ,

so ,

a sin A - b cos A / ( a sin A + b cosA )

= 0 /2sin A

= 0

Answer 2

Step-by-step explanation:

u can just write cos theta in form of base/perpendicular and find sin theta and cos theta nd just solve according to the question