If coto =1/√3 "write the value of" (1 – cos^2) /(2 – sin^2)
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Step-by-step explanation:
Let 'theta' to be 'A'
Cot A=1/√3
=> tan A=1/Cot A=√3
=> tan A=√3
We know that
Sec²A=1+tan²A
=>Sec A=√{1+(√3)²}=√(1+3)=√4=2
=> Sec A= 2
Cos A=1/Sec A=1/2
=> Cos A= 1/2
Sin A/CosA= tan A
=> SinA=tan A×Cos A=√3×(1/2)=√3/2
=>SinA=√3/2
=> Cosec A= 1/Sin A=2/√3
=> Cosec A=2/√3
All Trigonometric Functions are found
Question
(1-cos²A)/(2-Sin²A)
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