Question

if cotø + cosø = x and cotø - cosø = y then x²-y²=​

Answer 1

Answer:

4COT@COS@

Step-by-step explanation:

X+Y = 2COT@

X-Y = 2COS@

X2-Y2 = (X+Y)(X-Y) = 2COT@×2COS@ = 4COT@COS@

Answer 2

Answer:

(Cot theta +Cos theta)^2-(Cot theta -Cos theta)^2

open formula of (a+b)^2= a^2+b^2+2ab

and (a-b)^2=a^2+b^2-2ab

(Cot^2+ cos^2+2Cot Cos theta)_(Cot^2+Cos^2-2Cot Cos theta)

Cot^2+Cos^2+2Cot Cos theta-Cot^2-Cos^2+2Cot Cos theta

Now negative terms cancal with positive

sum of tow terms

4Cot Cos theta= x^2- y^2 Ans

Step-by-step explanation:

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