If cotx =1/2 and sec y =-5/2 ,where x lies in 3rd quadrant and y lies in 2nd quadrantfind the value of tan(x + y).
Answers
Answered by
4
cot x = 1/2 so tan x = 2
sec y = -5/2 so tan² y = 25/4 - 1 = 21/4
tan y = -√21 / 2 negative as y is in 2nd quadrant.
tan (x+y) = [tan x + tan y] / [1 - tan x tan y ]
= [2 - √21/2 ] / [ 1 + √21 ]
= [ 4 - √21 ] / [2 (1+√21) ]
sec y = -5/2 so tan² y = 25/4 - 1 = 21/4
tan y = -√21 / 2 negative as y is in 2nd quadrant.
tan (x+y) = [tan x + tan y] / [1 - tan x tan y ]
= [2 - √21/2 ] / [ 1 + √21 ]
= [ 4 - √21 ] / [2 (1+√21) ]
Similar questions