Question

If cow gives 2 litre milk buffalo gives 2 litre mik and goat gives 1/4 litre milk total animals should be 20 and milk also should be 20 litres

Answer 1

Answer:

Step-by-step explanation:

Let B = number of buffalo, C = number of cows, G = number of goats

Total number of animals = 20, so B + C + G = 20 (equation 1)

Total milk yield = 20 litres, so 8B + 8C + 1G =80 (equation 2)

But we need 3 simultaneous equations to solve for 3 variables. Let’s at least eliminate one of the variables.

Multiplying equation 2 by 4 gives: 8B + 8C + G = 80

Subtract equation 1:

B and C are both positive integers so

C = 8 and B + C <= 80

Finding C and G for all integral values of B between 11.11 and 15.79,where C = 20 - 8B and G = 20 - B - C:

Solution i) B = 12; C = 20 - (8× 12) G = 20 - 12

Solution ii) B = 13; C = 20 - (8× 13) G = 20 - 13

Solution iii) B = 14; C = 20 - (8 × 14) G = 20 - 14

Solution iv) B = 15; C = 20 - (8 x 15) ; G = 20 - 15

Checking milk yields, 2B + 2C + 0.25G:

Solution i) (2× 12) + (2 × 72) + (0.25 × 16) = 20

Solution ii) (2× 13) + (2 × 53) + (0.25 × 34) = 20

Solution iii) (2x 14) + (2× 34) + (0.25 × 52) = = 20

Solution iv) (2× 15) + (2x 15) + (0.25 × 70) = 20