If CP and Cv denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then relation between Cv and Cp is?
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Answered by
3
ΔQ=ΔU+PΔV
at constant volume ΔV=0
so, ΔQ=ΔU
Cv=ΔQ/ΔT =ΔU/ΔT
Cp=ΔQp/ΔT
=ΔU/ΔT+PΔV/ΔT
but ΔU/ΔT=Cv
Cp=Cv+PΔV/ΔT
but,PΔV/ΔT=nR
Cp=Cv+nR
n is number of moles
for 1 no of moles
Cp-Cv=R
at constant volume ΔV=0
so, ΔQ=ΔU
Cv=ΔQ/ΔT =ΔU/ΔT
Cp=ΔQp/ΔT
=ΔU/ΔT+PΔV/ΔT
but ΔU/ΔT=Cv
Cp=Cv+PΔV/ΔT
but,PΔV/ΔT=nR
Cp=Cv+nR
n is number of moles
for 1 no of moles
Cp-Cv=R
AllanDavis:
ans comes out to b Cp-Cv=R/28.......BUT I DONT KWM HOW?
Answered by
0
For one mole :
Cp-Cv=R
For unit mass :
Cp-Cv=R÷molar mass
Thus, for nitrogen gas Cp-Cv=R÷28
(Molar mass of nitrogen gas is 14×2=28)
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