Question

If critical temperature of a gas is 27°C . Then its inversion temp is

Answer 1

Tc=8a/(27Rb)

Ti=2a/Rb

by dividing them we get

Tc/Ti=8/(27×2)

given Tc=27°c=300K

Ti=(300×27×2)/8=16200/8

Ti=2025k

Ti=1752°C

hope the answer is helpful.