Question

If (CS) = 5500H, (IP) = 1200H, then the 20-bit physical address would be

Answer 1

Answer:

56200H

Explanation:

Effective address =Base address of CS register into 10H+ Address of IP

=5500H INTO 10H+1200H

=(55000+1200)H

=56200H

Answer 2

Given,

Base address of CS register  = 5500H

Address of IP = 1200H

To Find,

Physical address=?

Solution,

We know from the formula of the physical address for 20-bit is:

Physical address= Base address of CS register X 10H + Address of IP

Putting given values in a formula we get,

Physical address = $5500_H * 10_H + 1200_H$

Physical address = $55000_H + 1200_H$

Physical address = $56200_H$

Hence, the physical address is 56200$_H$