Question

If cu2+/cu electrode is diluted 100 times, then the change in emf is

Answer 1

Decreases by 59mv
According to Nernst equation,
Ecell=E°cell=-0.0591/z*l og(A(ox)/A(red)
As cu2+ is reductant and it's concentration is getting reduced by 100 times, so the log value will increase by the factor of 2. Also the value of z is 2. Thus, the overall E will decrease by 59mv

Answer 2

Answer:

Step-by-step explanation:

A . increase of 59 mV

B. decrease of 59 mV

C. increase of 29.5 mV

D. decrease of 29.5 mV

Electrode:

The definition of an electrode is that it can be any material that conducts electricity well. These materials are typically used to connect non-metallic components of a circuit, such as semiconductors, an electrolyte, plasmas, vacuum, or even air. William Whewell was the first to use the term, which is derived from the Greek terms elektron, which means "amber," and hodos, which means "a road."

Uses of Electrodes:

Electrodes are mostly used to create electrical current and transfer it through non-metal things to essentially change them in various ways. Conductivity can also be measured using electrodes.

Other applications for electrodes include electroplating, electrolysis, welding, cathodic protection, membrane electrode assembly, chemical analysis, and Taser electroshock weapons, to name a few.

Electrodes are also utilized in defibrillators, ECT, ECG, and other medical devices. In biomedical research, electrodes are also employed for electrophysiological methods.

1) Decrease by

2) By the Nearnst equation at $25oC,$ we have

3) E cell = E cell -  0.05916 V / z * log A ox / A red

4) Since Cu2+ is a reductant and its concentration is being reduced by 100 times, the log value will rise by a factor of 2. Z has a value of 2 as well.

Consequently, the overall E will drop by 59mV.

Hence option B is the correct answer decrease of 59mV.

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