Question

If cube root of (x/216) + 1/4 = 3/8 , then x is (The Question is the form of fractions)
(a) 3/4
(b) 27/64

Answer 1

Option B : 27/64

Step-by-step explanation:

$= > \sqrt[3]{ \frac{x}{216} } + \frac{1}{4} = \frac{3}{8} \\ = > \frac{ \sqrt[3]{x} }{6} + \frac{1}{4} = \frac{3}{8} \\ = > \frac{4 \sqrt[3]{x} + 6}{24} = \frac{3}{8} \\ = > 4 \sqrt[3]{x} + 6 = \frac{3 \times 24}{8} \\ = > 4 \sqrt[3]{x} + 6 = 9 \\ = > 4\sqrt[3]{x} = 9 - 6 \\ = > 4 \sqrt[3]{x} = 3 \\ = > \sqrt[3]{x} = \frac{3}{4} \\ = > x = ( \frac{3}{4} {)}^{3} \\ = > x = \frac{27}{64}$

Answer 2

Answer:

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