Question

if current changes at the rate of 4 ampere per second induced EMF of 20 mV in a solenoid then self inductance of the solenoid is​

Answer 1

Answer:

Emf= -L di/dt

• emf- 20×10^-3
• di/dt= 4

Put in formula

L = 5×10^-3; 5mHenry

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