If current flowing through the given circuit is 6A, find the value of unknown resistance R.
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Answer:
Applying Kirchhoff's second law in closed mesh AFEBA ,
9−6=I×1+I×1+4×0=0 (current in 4Ω is given zero)
or 3=2I
or I=3/2=1.5A
now in closed mesh AFEDCBA ,
9−3=I(1+1)+IR
or 6=1.5×2+1.5R
or 6=3+1.5R
or R=3/1.5=2Ω
now from point A to point D , (applying Kirchhoff's law for linear part AFED)
V
A
−I(1+1)=V
D
or V
A
−V
D
=1.5×2=3V
Explanation:
Answered by
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Answer:
attach the image then re-post the que
Explanation:
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