Question

if current of 10 ampere is passed through solution of AG NO3 for 5 minutes calculate amount of silver(AG) deposed when Z is 0.00033

Answer 1

since mass liberated Is directly proportional to the charge passed by Faraday's first law of electrochemistry therefore.....

q=z*I*t
q= 0.00033*(5*60)*10
q=0.99
so mass liberated is 0.99 gm

where time is taken in seconds . u can take time in minutes too