Question

if cylinders radius is increased by 50% and height is decreased by 50% how much percent its volume c hanges​

Answer 1

$\LARGE\color{black}{\colorbox{#FF7968}{Q}\colorbox{#4FB3F6}{u}\colorbox{#FEDD8E}{e}\colorbox{#FBBE2E}{s}\colorbox{#60D399}{t}\colorbox{#FF7968}{i}\colorbox{#FBBE2E}{o} \colorbox{#4FB3F6}{n}}$

if cylinders radius is increased by 50% and height is decreased by 50% how much percent its volume c hanges

$\LARGE\color{black}{\colorbox{#4FB3F6}{A}\colorbox{#FEDD8E}{n}\colorbox{#FBBE2E}{s}\colorbox{#60D399}{w}\colorbox{#FF7968}{e}\colorbox{#FBBE2E}{r} }$

237.5%

❥Hope you get your AnSwEr.

Answer 2

New volume > Original volume

Hence, there's a increase in volume.

Volume increased:-

$= \dfrac{9\pi {r}^{2} h}{8} - \dfrac{\pi {r}^{2} h}{1}</p><p> \\ \\ = \dfrac{9\pi {r}^{2} h - 8\pi {r}^{2}h }{8}</p><p>= \dfrac{\pi {r}^{2} h}{8}$

Increase in % is given by,

$= \rm \dfrac{increase \: in \: volume}{original \: volume} \times</p><p>= \dfrac{\pi {r}^{2}h }{8 \times \pi {r}^{2}h } \times$

100=8×πr2hπr2h×100

= 12.5\%=12.5%

${ \textsf{ \textbf{Hence, the increase in volume is \green{12.5\%}}}}$

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