Question

if D=-100 then root are​

Answer 1

3(k+19) = √1x219

[3(k+19)]²  = 1x219

a 5 digit number ending with 9

consider smallest value of x in the number 10219 square root is nearer to 100

consider greatest value of x in the number 19219 square root is nearer to 140

so 3(k + 19) lies between 100 and 4

the number is divisible by 3 and ending with 3 or 7

such numbers are 103, 107, 113, 117 123, 127, 133, 137

numbers divisible by 3 are 117 and 123

3(k + 19) = 117 or = 123

(k + 19) = 39 or = 41

k = 20 or 22

117² = 13689

123² = 15129 ------- I think you have written the digits reverse

x = 5

 

√0.05 * √0.5 * √x = 0.5 * 0.05 * √y

[√0.05 * √0.5 * √x]² = [0.5 * 0.05 * √y}²

0.05 × 0.5 × x = 0.25 × 0.0025y

x/y = 0.25 × 0.0025/0.05 × 0.5 = 0.025 ----------(a)

Answer 2

Answer:

this is your answer

hope you have understand