if d(3,-1),e(2,6),f(-5,7) are the mid points of the sides of triangle abc,then the area of triangle is
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D(3, -1) E (2, 6) F(-5, 7)
DE = √(7² + -1²) = 5√2 DE = (y-6) = -7(x-2) => y - 20 + 7x = 0
Length of perpendicular from F to DE, = | 7 - 20 -35 | / √(7²+1²) = 48/5√2
Area of DEF = 1/2 * 5√2 * 48/5√2 = 24 units
Total area of ABC is 4 times area of DEF => 96 units.
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