Question

If d=5,n=48.then what is difference between sum of 1st 24 terms &2nd 24 terms?

Answer 1

$\sf{\underline{Given:}}$

d = 5

n = 48

$\sf{\underline{To \:find:}}$

Difference between first 24 terms and second 24 terms

$\sf{\underline{Solution:}}$

Formula to find the sum of n terms of an AP with first term as a and common difference as d:

$\tt{s_{n} = \frac{n}{2} (2a + (n - 1)d}$

According to question:

a = a

d = 5

n = 48

$\tt{\frac{n'}{2} (2a + (n - 1)d - \frac{n}{2} ( 2a + (n' - 1)d}$

Here, n = 48

n' = 24

d = 5

=> $\tt{\frac{24}{2} (2a + 47(5) - 2a - 23(5)}$

=> 12(235 - 115)

=> 12(120)

=> 1440

_____________

Answer 2

Solutions:

The sum of n terms of an Ap with first term as a and common difference as d.

Ab = n/2(2a + (n - 1)d

a = a

d = 5

n = 45

n/2(2a + (n - 1)d - n/2(2a + (n - 1)d

n = 45

d = 5

24/2(2a + 47(5) - 2a - 23(5)

12(235 - 115)

12(120)

1440

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